S=-16t^2+0t+904

Solution for S=-16t^2+0t+904 equation:

=-16S^2+0S+904

We move all terms to the left:

-(-16S^2+0S+904)=0

We get rid of parentheses

16S^2-0S-904=0

We add all the numbers together, and all the variables

16S^2-1S-904=0

a = 16; b = -1; c = -904;
Δ = b2-4ac
Δ = -12-4·16·(-904)
Δ = 57857
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{57857}}{2*16}=\frac{1-\sqrt{57857}}{32}
$
$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{57857}}{2*16}=\frac{1+\sqrt{57857}}{32}
$